proposed by | Evgeny Selensky e.selensky@4c.ucc.ie |
The covering array problem is formulated as follows.
A covering array CA(t,k,g) of size b and strength t, is a k x b array A = (a_{ij}) over Z_g = {0,1,2,...,g-1} with the property that for any t distinct rows 1 <= r_1 <= r_2 <= ... <= r_t <= k, and any member (x_1, x_2, ..., x_t) of Z^t_g there exists at least one column c such that x_i equals the (r_i,c)-th element of A for all 1 <= i <= t.
A covering array number CAN(t,k,g) is the smallest b such that there exists a CA(t,k,g) of size b.
Informally, any t distinct rows of the covering array must encode column-wise all numbers from 0 to g^t-1 (repititions are allowed).
An example of covering array CA(3,5,2) over the Boolean alphabet {0,1} is:
0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 |
0 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 1 |
0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 1 |
0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 |
0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 1 |
In this array, any t = 3 rows encode all numbers from 0 (when the respective elements are {0,0,0}) to 2^3 - 1 = 7 (when the elements are {1,1,1}). E.g., the three top rows encode the following numbers (from left to right): 0,0,1,2,3,4,5,6,7,7; the three bottom rows encode numbers: 0,3,5,1,6,1,6,2,4,7.
It has been proved in [3] that CAN(3,5,2) = 10 and therefore the presented array is an optimal solution to CA(3,5,2).
The problem comes from hardware and software testing.
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