Programming Fundamentals

Information

  • This page contains extra challenge exercises for week 05.
  • These exercises are not compulsory, nor do they provide any marks in the course.
  • These exercises are intended for students that want more challenge in the course.
  • You cannot submit any of these exercises, however autotests are available for them (Command included at bottom of each exercise).

Exercise
(●●●)
:

Pointer Path

Download pointer_path.c here

Or, copy these file(s) to your CSE account using the following command:

1511 fetch-activity pointer_path

Your task is to add code to these functions in pointer_path.c:

// Prints the index-path from the given `start` index. Starts in the `pointers`
// array and bounces between pointers->indices->pointers->indices...
void print_pointer_path(
    int *pointers[MAX_SIZE],
    int indices[MAX_SIZE],
    int start
) {
    // TODO: Complete this function
}

As a quick initial remark, the syntax int *pointers[MAX_SIZE] can be read as "pointers is an array of length MAX_SIZE where each element is a pointer to an integer"

Now, the next thing to understand is that every integer we store in a variable has a memory address. This means that all integers in an array have individual memory addresses.

Using this idea, we once again consider the two arrays in the function above:

  • int *pointers[MAX_SIZE] is an array of int *
  • int indices[MAX_SIZE] is an array of int

This means that elements of pointers can point to addresses of elements in indices!

Likewise, elements of indices can store the indices of elements in pointers, and so we can have a two-way connection.

For this exercise, inputs will be taken for both arrays such that all elements in pointers will point to the addresses of elements in indices.

Conversely, all elements in indices will store an index into elements of pointers.

From here, you are to print the path from a starting index that is taken by bouncing between the two arrays until you are back at the starting index

Consider example input for the program below.

dcc pointer_path.c -o pointer_path
./pointer_path
Please enter which indices the pointer array will reference:
0 5 1 6 8 9 1 1 0 3
Please enter which indices the index array will reference:
5 5 3 2 0 8 1 6 7 9
What index will the path start at? 2
Pointer path: 2->1->5->9->9->3->end

In the initial 10 indices input, each number represents which index in the 'indices' array that an element in the 'pointers' array will reference.

For example:

  • pointers[0] will reference &indices[0]
  • pointers[1] will reference &indices[5]
  • pointers[2] will reference &indices[1]
  • pointers[3] will reference &indices[6]
  • And so on for all 10 indices...

Now, the next 10 indices act the same but in the reverse direction,

  • indices[0] will index pointers[5]
  • indices[1] will index pointers[5]
  • indices[2] will index pointers[3]
  • indices[3] will index pointers[2]

A full diagram has been provided for these relations below. The top array represents pointers and the bottom array represents indices. Do not try to understand it all at once as it can look quite messy. Simply pick an index and follow the outgoing line to see single relations.

Array Relations

Now, in the example, 2 was chosen as the start of the path. The diagram has been updated to show how the path is formed from this. Follow the red path from index 2 in the pointers array.

Array Relations

The path printed in the example above follows this:

  1. Starts at index 2 of pointers
  2. Moves to index 1 of indices
  3. Moves to index 5 of pointers
  4. Moves to index 9 of indices
  5. Moves to index 9 of pointers
  6. Moves to index 3 of indices
  7. Index 3 of indices contains index 2 to pointers, meaning we have reached the start again, so we stop

Examples

dcc pointer_path.c -o pointer_path
./pointer_path
Please enter which indices the pointer array will reference:
0 0 0 5 0 0 0 2 0 0
Please enter which indices the index array will reference:
0 0 3 0 0 7 0 0 0 0
What index will the path start at? 3
Pointer path: 3->5->7->2->end
./pointer_path
Please enter which indices the pointer array will reference:
5 3 1 9 9 5 4 2 8 0
Please enter which indices the index array will reference:
3 8 4 5 1 9 6 0 9 4
What index will the path start at? 4
Pointer path: 4->9->end
./pointer_path
Please enter which indices the pointer array will reference:
0 1 2 3 4 5 6 7 8 9
Please enter which indices the index array will reference:
1 2 3 4 5 6 7 8 9 0
What index will the path start at? 0
Pointer path: 0->0->1->1->2->2->3->3->4->4->5->5->6->6->7->7->8->8->9->9->end

Assumptions/Restrictions/Clarifications

  • All arrays will be of size MAX_SIZE
  • You will never have to deal with paths that don't make it back to the start index
  • All input indices will be valid
  • All elements in pointers will point to addresses of elements in indices
  • You can get the address of an element of indices by using &indices[i] where i is any index

When you think your program is working, you can use autotest to run some simple automated tests:

1511 autotest pointer_path

Exercise
(●●●)
:

Math with Function Pointers

Download function_pointers.c here

Or, copy these file(s) to your CSE account using the following command:

1511 fetch-activity function_pointers

Your task is to add code to these functions in function_pointers.c:

// Given an `operation`, return a pointer to the function that can perform
// that operation.
//
// E.g. if addition is the operation, a pointer to the `addition` function
// should be returned.
double (*get_operation_function(char operation))(double, double) {
    // TODO: COMPLETE THIS FUNCTION & CHANGE THIS RETURN
    return NULL;
}
// Performs an operation given various amounts of information.
void perform_operation(
    double first,
    double second,
    double (*operation_function)(double, double)
) {
    // TODO: COMPLETE THIS FUNCTION
}

For this exercise you will be exploring a new topic called Function Pointers. It is important to note that this is outside the scope of COMP1511 content, but is an interesting topic to look at.

Just like how we can store pointers to integers and doubles, we can actually store pointers to functions! This can be useful as we can also execute these functions as a result. This means that a single variable can reference and execute one function at a certain point in the program, and another function at another point!

Here is a basic program containing function pointers:

#include <stdio.h>

void add(int a, int b) {
    printf("%d + %d = %d\n", a, b, a + b);
}

void subtract(int a, int b) {
    printf("%d - %d = %d\n", a, b, a - b);
}

int main(void) {
    // Create a new variable `function_pointer` that points at the `add` function
    void (*function_pointer)(int, int) = &add;
    // Perform the `add` operation
    (*function_pointer)(10, 5);

    // Now, set the function pointer to point at the `subtract` function
    function_pointer = &subtract;
    // Call the function again, but this time, subtraction occurs!
    (*function_pointer)(10, 5);

    return 0;
}

The output of this program is:

10 + 5 = 15
10 - 5 = 5

The biggest challenge with function pointers is often the syntax of it. Here is a diagram that explains every section of the function_pointer variable declaration.

Labelled Function Pointer

It can also be seen from this that the function_pointer variable can only point at functions which take in two integers and return nothing.

Now, since function pointers have "types", it should be evident that they can also be used in both input and output of functions!

In this exercise, you are to implement the two functions seen above. The first function will return a different function pointer based on input. The second function will take in a function pointer as input to be used.

The actual program consists of constantly taking input from the user to perform mathematical operations. The user first enters an operation they want to perform ('+', '-', '*', '/'). You will be implementing a function get_operation_function that uses that input to return a pointer to the corresponding function for that operation.

If you look through the provided code, there are already addition, subtraction, multiplication and division functions implemented.

The user then enters 2 doubles as input to perform this operation on.

The next function you will need to implement is perform_operation which takes these two inputs as well as a function pointer and calls the function referenced by it, using the inputs as the parameters.

Examples

dcc function_pointers.c -o function_pointers
./function_pointers
Please enter an operation: +
Please enter 2 numbers to perform this operation on: 2 3
Applying this operation to 2.000000 and 3.000000 gives 5.000000
Please enter an operation: -
Please enter 2 numbers to perform this operation on: 5 3
Applying this operation to 5.000000 and 3.000000 gives 2.000000
Please enter an operation: *
Please enter 2 numbers to perform this operation on: 3 3
Applying this operation to 3.000000 and 3.000000 gives 9.000000
Please enter an operation: /
Please enter 2 numbers to perform this operation on: 5 2
Applying this operation to 5.000000 and 2.000000 gives 2.500000
Please enter an operation: 
./function_pointers
Please enter an operation: +
Please enter 2 numbers to perform this operation on: 1 1
Applying this operation to 1.000000 and 1.000000 gives 2.000000
Please enter an operation: +
Please enter 2 numbers to perform this operation on: 1 5
Applying this operation to 1.000000 and 5.000000 gives 6.000000
Please enter an operation: +
Please enter 2 numbers to perform this operation on: 100 100
Applying this operation to 100.000000 and 100.000000 gives 200.000000
Please enter an operation: /
Please enter 2 numbers to perform this operation on: 1000 1000
Applying this operation to 1000.000000 and 1000.000000 gives 1.000000
Please enter an operation: 
./function_pointers
Please enter an operation: *
Please enter 2 numbers to perform this operation on: 2 3
Applying this operation to 2.000000 and 3.000000 gives 6.000000
Please enter an operation: {
Invalid operation '{'
Please enter an operation: +
Please enter 2 numbers to perform this operation on: 5 4
Applying this operation to 5.000000 and 4.000000 gives 9.000000
Please enter an operation: 

If the user inputs an invalid command, return NULL; in the get_operation_function function. NULL is a standard way for programmers to identify if a pointer actually points anywhere of value

Assumptions/Clarifications/Restrictions

  • You can assume all number inputs will be valid
  • If you have a function pointer named func that takes 3 integers as input, it can be called by saying (*func)(1, 2, 3). The (*func) means dereference the pointer so we can get to the function, then the (1, 2, 3) is the giving the parameters

When you think your program is working, you can use autotest to run some simple automated tests:

1511 autotest function_pointers

Exercise
(●●●)
:

Conway's Game of Life

For this exercise, you are to write a program game_of_life.c that simulates Conway's Game of Life

This game consists of a 2D grid of cells. Each cell is said to be on 1 of 2 states:

  • Dead
  • Alive

In this game, the grid is said to change every "tick". The change that occurs depends on the states of each cell. Cells that are alive can die based on information about their neighbours and cells that are dead can come back to life under their own conditions.

There are many variations on what conditions are used to determine the next state of a cell. For this exercise, we will use the classic rules that were originally defined. These rules are listed below.

  • If an alive cell has 2 or 3 neighbours, it will be alive in the next state.
  • If a dead cell has exactly 3 neighbours, it will be alive in the next state.
  • If none of the above conditions are met, the cell in question is dead in the next state.

The neighbours of a given cell are the 8 surrounding cells. E.g. if you take a cell, it has a neighbour above, below, left, right and all diagonals to it.

In this exercise, you will take input from the user in the form of row/column pairs. These correspond to the cells that will be alive when the game starts. All other cells will be dead to begin with.

You will be required to work in a 20x20 array representing a total of 400 cells. In the original Game of Life, it is assumed that the grid is infinite, however, in our game, it will obviously be 20x20.

An addition that has been made as a result of this is that cells can wrap around the grid and have no edge restrictions. This means that cells in row 0 can be affect by cells in row 19, and the same goes for columns.

Sample Program

A fully implemented version of the application is provided below.

  • Click on the squares to make them alive (black means alive, white means dead)
  • Click on the Tick button to see what the next state of the grid will be. This can be repeated as much as you would like.
  • Click on the Play button to make the grid tick continuously.
  • Click on the Tick Frequency button to select the frequency of a tick
Presets (best used in 20x20 grid)
Tick frequency
Grid size

Example inputs and outputs of your program are provided below. Basic steps that you will need to implement are:

  1. Scan in an arbitrary number of pairs which index the grid. Each pair makes the corresponding cell alive.
  2. Continuously provide commands to manipulate the grid. Commands are:
    • p - Print the current grid
    • t n - "Tick" the grid n times where n is a positive integer
    • q - Quit the program

Examples

dcc game_of_life.c -o game_of_life
./game_of_life
Please enter the row and column of all alive cells. When finished, enter 'p'.
3 2
3 4
4 2
4 4
5 2
5 3
5 4
p
Current cell state:
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t 1
Ticked 1 times!
p
Current cell state:
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t 1
Ticked 1 times!
p
Current cell state:
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t 5
Ticked 5 times!
p
Current cell state:
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q
Exiting...

./game_of_life
Please enter the row and column of all alive cells. When finished, enter 'p'.
3 10
4 10
5 6
5 10
6 5
6 7
6 10
7 6
7 8
7 10
8 9
8 10
8 11
9 8
9 10
9 12
10 11
11 9
11 12
12 8
12 11
13 7
13 10
14 7
14 9
15 8
p
Current cell state:
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t 1
Ticked 1 times!
t 3
Ticked 3 times!
t 8
Ticked 8 times!
p
Current cell state:
.  .  .  .  .  .  .  .  .  #  .  .  #  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  #  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  #  #  .  #  .  .  #  .  .  .  .  .  .  
.  .  .  .  .  .  .  #  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  #  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  #  .  .  .  .  #  .  .  .  .  .  .  .  .  
.  .  .  .  .  #  .  .  .  .  .  .  #  #  .  .  .  .  .  .  
.  .  .  #  #  .  .  .  .  #  .  .  #  #  .  .  .  .  .  .  
.  .  .  #  .  .  .  .  .  #  #  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  #  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  #  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  #  .  .  .  #  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  #  #  #  .  .  .  .  .  .  .  .  
t 30
Ticked 30 times!
p
Current cell state:
.  .  .  .  .  #  #  .  .  #  #  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  #  #  #  #  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  #  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  #  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  #  #  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  #  #  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  #  #  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  #  #  .  .  .  #  #  .  .  .  .  
.  .  .  .  .  .  .  .  #  #  .  .  .  #  #  #  .  .  .  .  
.  .  .  .  .  .  .  .  .  #  #  #  .  .  #  #  .  .  .  .  
.  .  .  .  .  .  .  .  .  #  .  #  #  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  #  #  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  #  #  .  .  .  #  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  #  .  .  .  #  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  #  .  .  .  .  .  .  .  .  .  .  
t 100
Ticked 100 times!
p
Current cell state:
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
#  #  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  #  #  
#  #  #  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  #  #  
.  #  #  .  .  .  .  .  .  .  .  .  .  #  .  .  .  #  .  .  
.  #  .  .  .  .  .  .  .  .  .  .  #  .  .  .  .  .  .  .  
#  #  .  .  .  .  .  .  .  .  .  .  .  #  .  #  .  .  .  .  
#  #  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  #  #  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  #  #  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  #  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
.  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  .  
q
Exiting...

Due to the sheer size of these outputs, no more will be provided. However, the interactive above is a great place to test different inputs and copy them to your program then tick side-by-side to test output.

Assumptions/Restrictions/Clarifications

  • Your grid will always be 20x20 in size
  • Your grid can be of whatever type you wish (e.g. int, double, char). However, cells can only have 2 states so keep that in mind
  • You will never be given invalid row/column pairs
  • You may need to create two cell arrays, one for the current state and one for the next state

When you think your program is working, you can use autotest to run some simple automated tests:

1511 autotest game_of_life