#include <stdio.h>
#include <stdlib.h>


// Return the number of elements that are odd at
// corresponding indexes of both arr1 and arr2
int count_odd(int size1, int arr1[], int size2, int arr2[]) {
// if we had two lists instead of two arrays
// int count_odd(struct node *head1, struct node *head2)    
    int count = 0;
    int i = 0;
    // struct node *tmp1 = head1;
    // struct node *tmp2 = head2;
    while(i < size1 && i < size2) {   //while (tmp1 != NULL && tmp2 != NULL)
        if (arr1[i] % 2 != 0 && arr2[i] % 2 != 0) {
        // if (tmp->data % 2 != 0 && tmp2->data % 2 != 0)    
            count++;
        }
        i++;
        // tmp1 = tmp1->next;
        // tmp2 = tmp2->next;
    }
    return count;
}

int main(void) {

    // Only your function is called during testing
    // Any changes in this main function will not
    // be used in testing

    int array1[] = {9, -3, 1, 5, 2};
    int array2[] = {3, 2, -7, 6};

    printf("%d odd at the same index\n", count_odd(5, array1, 4, array2));

    return 0;
}