| Sort-Merge Join on Example (cont)
Case 2:   Join[id=stude](Student,Enrolled)
 
For the above, no re-scans of E runs are ever needed Student and Enrolled already sorted on id#
 memory buffers N=3 (S input, E input, output)
 5% of the "runs" in E span two pages
 there are no "runs" in S, since id# is a primary key
 
Cost  =  2,000 + 1,000  =  3,000   (regardless of which relation is outer)
 |