#// An example of a C program with a function with
#// one input and a return value

##include <stdio.h>
PRINT_INT=1
PRINT_STR=4

	.data
str1:
	.asciiz "Sum 1.. "
str2:
	.asciiz " = "
str3:
	.asciiz "\n"

	.text

main:	#int main(void) {
main__prologue:
	push	$ra
	push	$s0
main__body:
		
	li	$s0, 10		#int max = 10;
	move	$a0, $s0
	jal	sum_to		#int result = sum_to(max);
	move	$t0, $v0

	li	$v0, PRINT_STR
	la	$a0, str1
	syscall			#    printf("Sum 1.. ");

	li	$v0, PRINT_INT
	move	$a0, $s0 
	syscall			#    printf("%d", max);

	li	$v0, PRINT_STR
	la	$a0, str2
	syscall

	li	$v0, PRINT_INT
	move	$a0, $t0 
	syscall

	li	$v0, PRINT_STR
	la	$a0, str3
	syscall

	li	$v0, 0
main__epilogue:
	pop	$s0
	pop	$ra
	jr	$ra

sum_to:	#int sum_to(int n) {
	# sum in $t1, i in $t0, n in $a0
	li	$t1, 0		#sum = 0;
sum_to_loop_init:
	li	$t0, 1		#i = 1;
sum_to_loop_cond:
	bgt	$t0, $a0, sum_to_loop_end  # if (i > n) goto sum_to_loop_end;
sum_to_loop_body:
	add	$t1, $t1, $t0			#sum = sum + i;
sum_to_loop_step:
	addi	$t0, $t0, 1			#    i++;
	b	sum_to_loop_cond		#    goto sum_to_loop_cond;
sum_to_loop_end:
	move	$v0, $t1
	jr	$ra				#    return sum;