// Print an array of characters.

#include <stdio.h>

#define ARRAY_LEN 5

int main(void) {
    char array[ARRAY_LEN] = {'h', 'e', 'l', 'l', 'o'};

    for (int i = 0; i < ARRAY_LEN; i++) {
        printf("array[%d] = %c = %c = %c, ", i, array[i], i[array], *(array + i));
        printf("&array[%d] = %p = %p\n", i, &array[i], array + i);
        // &array[i] = array + 1 * i  - for an array of characters
        // &array[i] = array + sizeof(element) * i  - in general

        // Because addition is commutative, the following are equivalent:
        // array[i] = *(array + i);
        // i[array] = *(i + array)
    }
    return 0;
}

// What if we had
// int array[ARRAY_LEN] = {3, 1, 4, 1, 5}; ?
// &array[i] = array + 4 * i for an array of integers