// The following code is meant to prompt the user to enter a character and
// a string, then divide the string into two parts: 
// 1. the part before the character and 
// 2. the part after the character. 
// The two parts are then printed to the terminal.
//
// Unfortunately, this code contains a number of errors. 
// It's your job to fix them, good luck!

#include <stdio.h>
#include <string.h>

#define SIZE 50

void strip_newline(char *string);

int main(void) {
    char str[];

    printf("Enter a string: ");
    fgets(str, SIZE);
    strip_newline(str);

    char split_char;
    printf("Enter a character to split the string: ");
    scanf("%d", &split_char);

    int split_position = -1;
    length = strlen(str);

    for (int i = 0; i < length; i++) {
        if (str[i] == split_char && split_position == -1) {
            split_position = i;
        }
    }

    if (split_position == -1) {
        printf("Character not found in string.\n");
    }

    char before[];
    char after[];

    for (int i = 0; i < split_position; i++) {
        before[i] = str[i];
    }
    before[split_position] = '\0';

    for (int i = split_position; i < length; i++) {
        after[i - split_position - 1] = str[i];
    }
    after[length - split_position - 1] = '\0';

    printf("Before: %s\n", before);
    printf("After: %s\n", after);

    return 0;
}

////////////////////////////////////////////////////////////////////////////////
//                  DO NOT CHANGE ANY OF THE CODE BELOW HERE                  //
//      The code below is correct as given. You do NOT need to modify it      //
////////////////////////////////////////////////////////////////////////////////

// Removes a newline character from end of the given string, if it exists.
void strip_newline(char *string) {
    int length = strlen(string);
    if (length != 0 && string[length - 1] == '\n') {
        string[length - 1] = '\0';
    }
}