// A simple program demonstrating expressions
// Try to work out what will be printed without running the program


#include <stdio.h>

int main(void){
    int x = 4;
    int y = 3;
    int z = (x + y) * 10 - x;
    printf("%d\n", z);

    char c1 = 'a';
    char c2 = c1 + 1;
    printf("%c\n", c2);

    x = 3;
    y = 2;
    z = x / y;  // 3/2
    printf("%d\n", z);

    x = 3;
    y = 2;
    double w = x / y;
    printf("%lf\n", w);

    return 0;
}