// COMP1511 Array Print Pointer
// Print out the contents of an array, starting
// from index 0 and ending by printing out
// a particular element that is also being
// pointed at by a given pointer

// Marc Chee, March 2020

#include <stdio.h>

#define LENGTH 10

void array_print_pointer(int nums[LENGTH], int *last);

// This is a simple main function that you can use to 
// test your array_print_pointer function.
// It will not be marked - only your array_print_pointer 
// function will be marked.
//
// Note: the autotest does not call this main function!
// It calls your array_print_pointer function directly.
// Any changes that you make to this main function will 
// not affect the autotests.

int main(int argc, char *argv[]){
   int nums[LENGTH] = {1,2,3,4,5,6,7,8,9,10};
   int *last = &nums[5];

   // Pass in the array and a pointer to the 
   // last element that should be printed
   array_print_pointer(nums, last);

   int nums2[LENGTH] = {1,5,4,3,5,6,7,8,9,10};
   int *last2 = &nums2[8];

   // Pass in the array and a pointer to the 
   // last element that should be printed
   array_print_pointer(nums2, last2);
   return 0;
}

// Print an array from the beginning until it reaches
// a pointer to one of the elements. That element is
// the last thing printed out.

// Assumes that the pointer is aimed at one of the array elements.
void array_print_pointer(int nums[LENGTH], int *last) {
    printf("I should output some elements of the array.\n");
}