// This program demonstrates the use of command line arguments
// We are used to seeing int main(void), where no inputs are given to our
// main function when it first runs. What if we were to change that to allow
// the main function to accept arguments on running? 

// Sasha Vassar Week 5, Lecture 10


#include <stdio.h>

int main (int argc, char *argv[]) {
     
    printf("There are %d command line arguments in this program\n", argc);
    //argv[0] is always the program name
    printf("The program name is located in argv[0] and is %s\n", argv[0]);
    //./argv_demo Alvin
    //argv[0] = ./argv_demo
    //argv[1] = "Alvin"
    //argv[1][0] = 'A'
    //argv[1][1] = 'l'
    printf("argv[3][0] = %c\n", argv[3][0]);
    //Let's now print out all the command line arguments given 
    int i = 1;
    while (i < argc) {
        printf("The command line argument at index %d (argv[%d]) is %s\n",
         i, i, argv[i]);
        i++;
    }
    return 0;
}