// Demonstrating using IF statements
// with logical operators
// Sasha Vassar, Week 2 Lecture 3

// AND && 
// OR || 


#include <stdio.h>

// Problem 1: Let the user provide you a number, that you then check 
// and decide how many digits that number has. 

// Problem 2: Let's extend the problem, the user now provides you two
// numbers, that you add together and then check and decide how many
// digits the sum has.

int main (void) {

// 1. Let the user provide number - scanf()
// 2. Check for number of digits - 
// -10 < x < 10 1 digit
// 10 <= x < 100 2 (digits) -100 < x <= -10 
// 3. Print out the number of digits - printf()

    int sum;
    int number_one;
    int number_two;
    int scanf_return;
    printf("Please enter two numbers: ");
    // scanf has a return value - the number of things it has scanned in.
    
    scanf_return = scanf("%d %d", &number_one, &number_two);
    printf("scanf_return: %d\n", scanf_return);
    
    if (scanf_return != 2) {
        printf("Error, a number was not scanned in\n");
        return 1;
    }
    sum = number_one + number_two;
    
    if (-10 < sum && sum < 10) {
        printf("%d has 1 digit\n", sum);
    } else if ((10 <= sum && sum < 100) || (-10 >= sum && sum > -100)) {
        printf("%d has 2 digits.\n", sum);
    } else if (sum >= 100 || sum <= -100) {
        printf("%d has more than 2 digits.\n", sum);
    }
    
    return 0;
}